Question

use the standard normal distribution table to determine the missing values of the following probability. P(0≤Z≤?)=0.4884

Answer #1

**Solution-**

**P( 0 ≤ Z ≤ 2.2701 ) = 0.4884**

Use the standard normal (z score) table to find: P(-1.00 ≤
z)
Find the probability that a data value picked at random from a
normal population will have a standard score (z) that lies between
the following pairs of z-values. z = 0 to z = 2.10

Find the following z values for the standard normal
variable Z. Use Table 1. (Negative values should
be indicated by a minus sign. Round your answers to 2 decimal
places.)
a.
P(Z ≤
z) = 0.9478
b.
P(Z >
z) = 0.6140
c.
P(−z ≤
Z ≤ z) = 0.80
d.
P(0 ≤ Z ≤
z) = 0.2392
Hints

In a standard normal distribution, find the probability P(z >
1.02).
In a standard normal distribution, find the probability P(z <
-.35).

Table 1: Cumulative distribution function of the standard Normal
distribution
z: 0 1 2 3 Probability to the left of z: .5000 .84134 .97725 .99865
Probability to the right of z: .5000 .15866 .02275 .00135
Probability between z and z: .6827 .9544 .99730
Table 2: Inverse of the cumulative distribution function of the
standard Normal distribution
Probability to the left of z: . 5000 .92 .95 .975 .9990 z: 0.00
1.405 1.645 1.960 3.09
1 Normal Distributions
1. What proportion...

Find the following z values for the standard normal variable Z.
(Use Excel command instead of the z table. Negative values should
be indicated by a minus sign. Round your answers to 2 decimal
places.)
a.
P(Z ≤ z) = 0.9477
b.
P(Z > z) = 0.63
c.
P(−z ≤ Z ≤ z) = 0.85
d.
P(0 ≤ Z ≤ z) = 0.2034

Find the probability using the normal
distribution:P(0<z<2.56). use the cumulative normal
distribution table and enter the answer to 4 decimal places.

For a random variable Z, that follows a standard normal
distribution, find the values of z required for these probability
values
P(Z<z)=.5
P(Z<z)=.1587
P(Z<z)=.8413

Determine Z and X values for a given probability. Z is standard
normal, X is normal.
Given
μ = 12 (Units not given)
σ = 3.2 (Units not
given)
The probability in the upper
tail is:
α = 0.095 (Unitless)
Determine the Z Value associated with the probability and
calculate the X Value associated with the Z value.

For a standard normal distribution, determine the probabilities
of obtaining the following z values. It is helpful to draw
a normal distribution for each case and show the corresponding
area.
(a)
greater than zero
(b)
between −2.0 and −1.5
(c)
less than 1.5
(d)
between −1.2 and 1.2
(e)
between 1.35 and 1.85

For a standard normal distribution, find: P(-1.73 < z <
-0.77)
For a standard normal distribution, find: P(z > c) = 0.9494
Find c.
Assume that z-scores are normally distributed with a mean of 0
and a standard deviation of 1.
If P(z>c)=0.2789 P(z>c)=0.2789 , find c
Assume that z-scores are normally distributed with a mean of 0
and a standard deviation of 1. If P(z>d)=0.7887 P(z>d)=0.7887
, find d.
Assume that z-scores are normally distributed with a mean of...

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