X has a normal distribution with the given mean and standard deviation. Find the indicated probability. (Round your answer to four decimal places.)
μ = 39, σ = 20, find
P(32 ≤ X ≤ 49)
Solution :
Given that ,
mean = = 39
standard deviation = = 20
P( 32 x 49 )
= P[(32 - 39 / 20) (x - ) / (49 - 39 / 20) ]
= P( -0.35 z 0.5 )
= P(z 0.5 ) - P(z -0.35 )
Using z table,
= 0.6915 - 0.3632
= 0.3283
P( 32 x 49 ) = 0.3283
Probability = 0.3283
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