A population, with an unknown distribution, has a mean of 80 and a standard deviation of 7. For a sample of 49, the probability that the sample mean will be larger than 82 is
Group of answer choices
About .516
About 0.0228
About 0.9772
About 0.484
Given that ,
mean = = 80
standard deviation = = 7
n = 49
= 80
= / n =7 / 49 =1
P( >82 ) = 1 - P( <82 )
= 1 - P[( - ) / < (82 -80) /1 ]
= 1 - P(z <2 )
Using z table
= 1 - 0.9772
= 0.0228
probability= 0.0228
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