A population has a mean of 50 and a standard deviation of 8. A sample of 64 observations will be taken. The probability that the mean from that sample will be larger than 49 is
a)0.1587
b)0.8413
c)0.0228
d)0.9772
Solution :
Given that ,
mean = = 50
standard deviation = = 8
n = 64
= 50
= / n = 8 / 64= 1
P( > 49) = 1 - P( < 49)
= 1 - P[( - ) / < (49 -50) / 1]
= 1 - P(z <-1 )
Using z table
= 1 - 0.1587
= 0.8413
probability= 0.8413
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