A physics class has 50 students. Of these, 10 students are physics majors and 17 students are female. Of the physics majors, three are female. Find the probability that a randomly selected student is female or a physics major.
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We are assuming that the randomly selected student is a female or a physics major or both.
Total students = 50
P(Female) = P(F) = 17/50
P(Physics major) = P(M) = 10/50
P( Physics major | Female) = P(M | F) = 3/50
So, it's asking you for the union of Female and Physics major. The formula for union is
P ( M U F ) = P(M) + P(F) - P(M | F) = 10/50 + 17/50 - 3/50 = 0.480
You can think of this as adding all the female and physics major and then subtracting all of the female physics major since they are counted twice.
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