Here is a data set:
303 | 288 | 224 | 283 |
365 | 264 | 274 | 297 |
300 | 447 | 297 | 325 |
249 | 387 | 294 | 383 |
369 | 348 | 375 | 359 |
381 | 380 | 203 | 402 |
256 | 382 | 330 | 258 |
Construct a grouped frequency distribution table (GFDT) for this
data set. You want 10 classes with a "nice" class width. A "nice"
class width would be a multiple of 5 or 10. Your classes should be
labeled using interval notation. Since the data appears to be
discrete, use a closed-interval to label each class. Each class
should contain its lower class limit, and the lower class limits
should all be multiples of the class width.
(Note: interval notation for closed intervals will take the
following form "[number,number]")
Data range | Frequency |
---|---|
There are 10 classes, with class width 25, a multiple of 5. The highest number in the data is 447 and lowest 203 so we take the nearest integers to them which are a multiple of 5, i.e. 450 and 200 respectively to construct the classes.
Classes are denoted using closed interval notations. For
example, [200,225] means greater than or equal to 200 and less than
or equal to 225. According to the problem, each class should
contain its lower class limit, hence in [200,225] for example, we
will count the value 200, and not 225 if there are any. We will
count 225 in the following class [225,250].
Thus we get,
Data range | Frequency |
[200,225] | 2 |
[225,250] | 1 |
[250,275] | 4 |
[275,300] | 5 |
[300,325] | 2 |
[325,350] | 3 |
[350,375] | 3 |
[375,400] | 6 |
[400,425] | 1 |
[425,450] | 1 |
Get Answers For Free
Most questions answered within 1 hours.