Question
The numbers of online applications from simple random samples of college applications for 2004 and for...
The numbers of online applications from simple random samples of
college applications for 2004 and for the 2009 were taken. In 2004,
out of 336 applications, 131 of them were completed online. In
2009, out of 379 applications, 125 of them were completed online.
Test the claim that the proportion of online applications in 2009
was equal to than the proportion of online applications in 2004 at
the .10 significance level.
Claim: Select an answer p 1 ≤ p 2 u 1 < u 2 p 1 ≥ p 2 p 1≠p 2 u
1 ≥ u 2 u 1 = u 2 u 1≠u 2 u 1 ≤ u 2 p 1 < p 2 p 1 = p 2 u 1 >
u 2 p 1 > p 2 which corresponds to Select an answer
H1: u 1 < u 2 H0: p 1 = p 2 H0: p 1≠p 2 H1: p 1≠p 2 H1: p 1 <
p 2 H1: u 1 > u 2 H0: p 1 ≤ p 2 H1: p 1 > p 2 H0: u 1 ≤ u 2
H1: u 1≠u 2
Opposite: Select an answer u 1 ≤ u 2 p 1 = p 2 u 1 ≥ u 2 u 1≠u 2 p
1 ≤ p 2 p 1 > p 2 p 1 < p 2 p 1 ≥ p 2 u 1 < u 2 u 1 > u
2 u 1 = u 2 p 1≠p 2 which corresponds to Select an
answer H1: u 1 = u 2 H1: p 1 > p 2 H1: p 1≠p 2 H0: p 1≠p 2 H0: p
1 = p 2 H1: u 1 <= u 2 H1: u 1 ≥ u 2 H0: u 1≠u 2 H1: p 1 < p
2 H0: u 1 > u 2 H0: p 1 ≤ p 2
The test is: Select an answer two-tailed right-tailed
left-tailed
The test statistic is: zz = Select an answer 1.67 1.87 1.2 1.36
1.82 (to 2 decimals)
The critical value is: zα2zα2= ±± Select an
answer 1.15 1.64 1.64 1.44 1.28 (to
2 decimals)
Based on this we: Select an answer Cannot determine anything Accept
the null hypothesis Fail to reject the null hypothesis Reject the
null hypothesis
Conclusion There Select an answer does not
does appear to be enough evidence to support the claim
that the proportion of online applications in 2009 was equal to
than the proportion of online applications in 2004.
Homework Answers
Answer #1
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