NBC claims that viewers spend a daily average of 98.8 minutes
watching their content. An advertiser wants to verify this and
conducts a poll of 33 random viewers who claim to watch NBC. The
poll showed that this group spends a daily average of 88.9 minutes
watching NBC with a standard deviation of 20.7 minutes. Use a 0.005
significance level to test the claim that the daily average amount
of time NBC viewers watch NBC is less than 98.8 minutes, the
average amount claimed by NBC..
Claim: Select an answer u = 98.8 p < 98.8 p ≤ 98.8 u < 98.8 u
≤ 98.8 u ≥ 98.8 p ≠ 98.8 u > 98.8 p > 98.8 p = 98.8 p ≥ 98.8
u ≠ 98.8 which corresponds to Select an answer H1: u
< 98.8 H0: p ≥ 98.8 H0: u ≠ 98.8 H0: u = 98.8 H1: u > 98.8
H0: u ≤ 98.8 H1: u ≠ 98.8
Opposite: Select an answer u = 98.8 p ≥ 98.8 p > 98.8 u >
98.8 u ≥ 98.8 u ≤ 98.8 p < 98.8 p ≤ 98.8 p = 98.8 u < 98.8 p
≠ 98.8 u ≠ 98.8 which corresponds to Select an answer
H0: p ≥ 98.8 H0: u ≤ 98.8 H1: u < 98.8 H0: u = 98.8 H0: u ≠ 98.8
H1: u > 98.8 H1: u ≠ 98.8
The test is: Select an answer left-tailed two-tailed
right-tailed
The test statistic is: Select an answer -2.35 -2.75 -2.62 -2.46
-3.25
The Critical Value is: Select an
answer -2.739 -2.733 -2.899 -2.968 -3.1
Based on this we: Select an answer Reject the null hypothesis Fail
to reject the null hypothesis
Conclusion There Select an answer does not
does appear to be enough evidence to support the claim
that the daily average amount of time NBC viewers watch NBC is less
than 98.8 minutes, the average amount claimed by NBC..
Solution:
1)
Claim: < 98.8
2)
H1: < 98.8
H0: = 98.8
3)
The test is left-tailed .
4)
The test statistics t is given by ..
t =
= (88.9 - 98.8)/(20.7/33)
= -2.75
5)
df = n - 1 = 33 - 1 = 32
= 0.005
For left tailed test , critical value is
2.739
6)
Reject the null hypothesis
7)
There does appear to be enough evidence to support the claim that the daily average amount of time NBC viewers watch NBC is less than 98.8 minutes, the average amount claimed by NBC..
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