Question

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. This method is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect, so the probability of a girl is

0.50.5.

Assume that the groups consist of

2929

couples. Complete parts (a) through (c) below.

a. Find the mean and the standard deviation for the numbers of girls in groups of

2929

births.The value of the mean is

muμequals=nothing.

(Type an integer or a decimal. Do not round.)

The value of the standard deviation is

sigmaσequals=nothing.

(Round to one decimal place as needed.)

b. Use the range rule of thumb to find the values separating results that are significantly low or significantly high.

Values of

nothing

girls or fewer are significantly low.

(Round to one decimal place as needed.)

Values of

nothing

girls or greater are significantly high.

(Round to one decimal place as needed.)

c. Is the result of

2222

girls a result that is significantly high? What does it suggest about the effectiveness of the method?The result

▼

is not

is

significantly high, because

2222

girls is

▼

greater than

less than

equal to

nothing

girls. A result of

2222

girls would suggest that the method

▼

is not effective.

is effective.

(Round to one decimal place as needed.)

Answer #1

Assume that different groups of couples use a particular method
of gender selection and each couple gives birth to one baby. This
method is designed to increase the likelihood that each baby will
be a girl, but assume that the method has no effect, so the
probability of a girl is 0.5. Assume that the groups consist of 34
couples. Complete parts (a) through (c) below. a. Find the mean
and the standard deviation for the numbers of girls in...

Assume that different groups of couples use a particular method
of gender selection and each couple gives birth to one baby. This
method is designed to increase the likelihood that each baby will
be a girl, but assume that the method has no effect, so the
probability of a girl is 0.5. Assume that the groups consist of 48
couples.Complete parts (a) through (c) below.
a. Find the mean and the standard deviation for the numbers of
girls in groups...

A gender-selection technique is designed to increase the
likelihood that a baby will be a girl. In the results of the
gender-selection technique, 933 births consisted of 470 baby girls
and 463 baby boys. In analyzing these results, assume that boys
and girls are equally likely. a. Find the probability of getting
exactly 470 girls in 933 births. b. Find the probability of getting
470 or more girls in 933 births. If boys and girls are equally
likely, is 470...

The accompanying data table describes results from groups of 10
births from 10 different sets of parents. The random variable x
represents the number of girls among 10 children. Complete the
questions below.
x P(x)
0 0.002
1 0.016
2 0.037
3 0.114
4 0.201
5 0.238
6 0.198
7 0.113
8 0.045
9 0.014
10 0.022
The maximum usual value is (Round to one decimal place as
needed.)
The minimum usual value is (Round to one decimal place as...

A clinical trial tests a method designed to increase the
probability of conceiving a girl. In the study 480 babies were
born,
and 264 of them were girls. Use the sample data to construct a 99%
confidence interval estimate of the percentage of girls
born. Based on the result, does the method appear to be
effective?
< p < (Round to three decimal places as needed.)
Does the method appear to be effective?
Yes, the proportion of girls is significantly...

A clinical trial tests a method designed to increase the
probability of conceiving a girl. In the study 480 babies were
born,
and 264 of them were girls. Use the sample data to construct a 99%
confidence interval estimate of the percentage of girls
born. Based on the result, does the method appear to be
effective?
< p < (Round to three decimal places as needed.)
Does the method appear to be effective?
Yes, the proportion of girls is significantly...

Five males with a particular genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the genetic disorder. Determine whether the table
describes a probability distribution. If it does, find the mean
and standard deviation.
x
0
1
2
3
4
5
P(x)
0.01160.0116
0.08340.0834
0.23990.2399
0.34520.3452
0.24840.2484
0.07150.0715
Find the mean of the random variable x. Select the correct
choice below and, if necessary, fill in the answer box...

Five males with a particular genetic disorder have one child
each. The random variable x is the number of children among the
five who inherit the genetic disorder. Determine whether the table
describes a probability distribution. If it does, find the mean
and standard deviation.
x
0
1
2
3
4
5
P(x)
0.00020.0002
0.00530.0053
0.04500.0450
0.19190.1919
0.40890.4089
0.34870.3487
Find the mean of the random variable x. Select the correct
choice below and, if necessary, fill in the answer box...

Assume that
31.4%
of people have sleepwalked. Assume that in a random sample
of
1491
adults,
477
have sleepwalked.a. Assuming that the rate of
31.4%
is correct, find the probability that
477
or more of the
1491
adults have sleepwalked.b. Is that result of
477
or more significantly high?c. What does the result suggest
about the rate of
31.4%?
a. Assuming that the rate of
31.4%
is correct, the probability that
477
or more of the
1491
adults have sleepwalked...

A sociologist randomly selects single adults for different
groups of three, and the random variable x is the number in the
group who say that the most fun way to flirt is in person.
Determine whether a probability distribution is given. If a
probability distribution is given, find its mean and standard
deviation. If a probability distribution is not given, identify
the requirements that are not satisfied.
x
P(x)
0
0.0940.094
1
0.3370.337
2
0.4030.403
3
0.1660.166
Does the table...

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