A film distribution manager calculates that 9% of the films released are flops. If the manager is right, what is the probability that the proportion of flops in a sample of 435 released films would differ from the population proportion by greater than 4%? Round your answer to four decimal places.
Solution :
Given that ,
p = 0.09
1 - p = 1- = 0.91
n = 435
= p = 0.09
= (p*(1-p))/n = (0.09*0.91)/435 = 0.01372
P(0.05 < <0.13 ) = P((0.05-0.09)/0.01372 ) < ( - ) / < (0.13-0.09) /0.01372 ) )
= P(-2.915 < z < 2.915 )
= 1-(P(z < 2.915) - P(z < -2.915))
= 1 - ( 0.9982 - 0.0018)
= 1 - 0.9964
= 0.0036
Probability = 0.0036
The probability that the proportion of flops in a sample of 435 released films would differ from the population proportion by greater than 4% is 0.0036
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