A film distribution manager calculates that 9% of the films released are flops.
If the manager is accurate, what is the probability that the proportion of flops in a sample of 864 released films would be less than 8%?
Round your answer to four decimal places.
Solution
Given that,
p = 0.09
1 - p = 1-0.09=0.91
n = 864
= p =0.09
= [p ( 1 - p ) / n] = [(0.09*0.91) /864 ] = 0.009736
P( <0.08 ) =
= P[( - ) / < (0.08-0.09) / 0.009736]
= P(z < -1.03)
Using z table,
probability =0.1515
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