You measure 29 textbooks' weights, and find they have a mean weight of 71 ounces. Assume the population standard deviation is 14.1 ounces. Based on this, construct a 99% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places.
Solution :
Given that,
Sample size = n = 29
Z/2 = 2.576
Margin of error = E = Z/2* ( /n)
= 2.576 * (14.1 / 29)
Margin of error = E = 6.74
At 99% confidence interval estimate of the population mean is,
- E < < + E
71 - 6.74 < < 71 + 6.74
64.26 < < 77.74
(64.26 , 77.74)
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