In a survey, 25 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $45 and standard deviation of $9. Construct a confidence interval at a 80% confidence level. Give your answers to one decimal place.
Solution :
Given that,
Z/2 = Z0.10 = 1.282
Margin of error = E = Z/2
* (
/n)
= 1.282 * ( 9 / 25
)
= 2.3
At 80% confidence interval estimate of the population mean is,
± E
= 45 ± 2.3
= ( $ 42.7, $ 47.3 )
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