A market researcher is studying the spending habits of pople across age groups. The amount of money spent by each individual is classified by spending category (Dining out, Shopping, or Electronics) - Factor A, and generation (Gen-X, Gen-Y, Gen-Z, or Baby Boomers) - Factor B. An incomplete ANOVA table is shown below. At the 5% significance level, the conclusion of the hypothesis test for factor A is
Source of Variation |
SS |
df |
MS |
F |
p-value |
F crit |
Rows (Factor B) |
1.42 |
0.3398 |
2.92 |
|||
Columns (Factor A) |
3.15 |
0.0340 |
2.32 |
|||
Error |
455 |
16.25 |
||||
Total |
1,321 |
35 |
reject the null hypothesis; we cannot conclude the average amout spent differs by spending category
reject the null hypothesis; the average amout spent differs by spending category
do not reject the null hypothesis; we cannot conclude the average amout spent differs by spending category
do not reject the null hypothesis; the average amout spent differs by spending category
Solution:
Given:
Source of Variation |
SS |
df |
MS |
F |
p-value |
F crit |
---|---|---|---|---|---|---|
Rows (Factor B) |
1.42 |
0.3398 |
2.92 |
|||
Columns (Factor A) |
3.15 |
0.0340 |
2.32 |
|||
Error |
455 |
16.25 |
||||
Total |
1,321 |
35 |
Factor A: spending category (Dining out, Shopping, or Electronics)
H0: the average amout spent does not differs by spending category.
Vs
H1: the average amout spent differs by spending category.
Decision Rule:
Reject null hypothesis H0, if P-value < 0.05 level of
significance, otherwise we fail to reject H0
Since p-valuefor Factor A is 0.0340 < 0.05 level of significance, hence we reject the null hypothesis of no difference in the average amout spent by spending category.
Thus:
At the 5% significance level, the conclusion of the hypothesis test for factor A is:
Reject the null hypothesis; the average amout spent differs by spending category.
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