Question

Find the regression​ equation, letting overhead width be the predictor​ (x) variable. Find the best predicted weight of a seal if the overhead width measured from a photograph is 1.6 cm. Can the prediction be​ correct? What is wrong with predicting the weight in this​ case? Use a significance level of 0.05.

Overhead_Width_(cm)   Weight_(kg)
7.5    152
7.8      195
8.7      229
9.6      242
7.6      177
8.2      208

The regression equation is ^y = ? + ?x
(Round to one decimal place as​ needed.)

The best predicted weight for an overhead width of
1.6 cm is ? kg.
(Round to one decimal place as​ needed.)

Can the prediction be​ correct? What is wrong with predicting the weight in this​ case?

A.
The prediction cannot be correct because a negative weight does not make sense. The width in this case is beyond the scope of the available sample data.
This is the correct answer.

B.
The prediction cannot be correct because a negative weight does not make sense and because there is not sufficient evidence of a linear correlation.
Your answer is not correct.

C.
The prediction cannot be correct because there is not sufficient evidence of a linear correlation. The width in this case is beyond the scope of the available sample data.

D.
The prediction can be correct. There is nothing wrong with predicting the weight in this case.

Answer 1

The prediction cannot be correct because a negative weight does not make sense. The width in this case is beyond the scope of the available sample data.