Find the regression equation, letting the first variable be the predictor (x) variable. Using the listed lemon/crash data, where lemon imports are in metric tons and the fatality rates are per 100,000 people, find the best predicted crash fatality rate for a year in which there are 450 metric tons of lemon imports. Is the prediction worthwhile?
Lemon Imports 231 268 350 461
550
Crash Fatality Rate 15.9 15.6
15.2 15.3 15
Find the equation of the regression line.
y =_______+_______x (Round the constant three decimal places as
needed. Round the coefficient to six decimal places as
needed.)
The best predicted crash fatality rate for a year in which there
are 450 metric tons of lemon imports is ______fatalities per
100,000 population.
(Round to one decimal place as needed.)
sr | x | y | (x-xbar)^2 | (y-ybar)^2 | (x-xbar)*(y-ybar) |
1 | 231 | 15.9 | 19881 | 0.25 | -70.5 |
2 | 268 | 15.6 | 10816 | 0.04 | -20.8 |
3 | 350 | 15.2 | 484 | 0.04 | 4.4 |
4 | 461 | 15.3 | 7921 | 0.01 | -8.9 |
5 | 550 | 15 | 31684 | 0.16 | -71.2 |
sum | 1860 | 77 | 70786 | 0.5 | -167 |
mean | 372 | 15.4 | SXX | SYY | Sxy |
slope=sxy/sxx | -0.002359224 | -0.1226796 | |||
intercept=ybar-(slope*xbar) | 16.27763117 | 16.154952 |
equation of the regression line
Y^ = 16.278 - 0.002359 *x
put x = 450 in above equation
Y^ = 16.278 - 0.002359 *450
y^=15.2
The best predicted crash fatality rate for a year in which there are 450 metric tons of lemon imports is 15.2 fatalities per 100,000 population
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