Question

Find the regression equation, letting the first variable be the predictor (x) variable. Using the listed lemon/crash data, where lemon imports are in metric tons and the fatality rates are per 100,000 people, find the best predicted crash fatality rate for a year in which there are 450 metric tons of lemon imports. Is the prediction worthwhile?

Lemon Imports 231 268 350 461
550

Crash Fatality Rate 15.9 15.6
15.2 15.3 15

**Find the equation of the regression line.**

y =_______+_______x (Round the constant three decimal places as
needed. Round the coefficient to six decimal places as
needed.)

The best predicted crash fatality rate for a year in which there
are 450 metric tons of lemon imports is ______fatalities per
100,000 population.

(Round to one decimal place as needed.)

Answer #1

sr |
x |
y |
(x-xbar)^2 |
(y-ybar)^2 |
(x-xbar)*(y-ybar) |

1 | 231 | 15.9 | 19881 | 0.25 | -70.5 |

2 | 268 | 15.6 | 10816 | 0.04 | -20.8 |

3 | 350 | 15.2 | 484 | 0.04 | 4.4 |

4 | 461 | 15.3 | 7921 | 0.01 | -8.9 |

5 | 550 | 15 | 31684 | 0.16 | -71.2 |

sum | 1860 | 77 | 70786 | 0.5 | -167 |

mean | 372 | 15.4 | SXX | SYY | Sxy |

slope=sxy/sxx |
-0.002359224 |
-0.1226796 | |||

intercept=ybar-(slope*xbar) |
16.27763117 |
16.154952 |

equation of the regression line

Y^ = 16.278 - 0.002359 *x

put x = 450 in above equation

Y^ = 16.278 - 0.002359 *450

y^=15.2

The best predicted crash fatality rate for a year in which there
are 450 metric tons of lemon imports is **15.2**
fatalities per 100,000 population

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