Question

Assume that population means are to be estimated from the samples described. Use the sample results to approximate the margin of error and 95% confidence interval. Sample size- 1,042 Sample mean - 46,245 Standard Deviation- 26,000

1-The margin of error is

2-Find the 95% confidence interval.

Answer #1

Assume that population means are to be estimated from the
samples described. Use the sample results to approximate the margin
of error and 95% confidence interval.
Sample size=1,048,
sample mean=$46,209,
sample standard deviation=$21,000
The margin of error is $ __

Assume that population mean is to be estimated from the sample
described. Use the sample results to approximate the margin of
error and 95% confidence interval. Sample size, n=64; sample
mean, x overbare=83.0 cm; sample standard deviation, s=4.0
cm.
The margin of error is ____ cm. (Round to one decimal place as
needed.)

Assume that population mean is to be estimated from the sample
described. Use the sample results to approximate the margin of
error and 95% confidence interval.
n=49, x=56.1 seconds, s=5.1 seconds

Assume that population proportion is to be estimated from the
sample described. Use the sample results to approximate the margin
of error and 95% confidence interval.
n=560, p-0.65 Round to four decimal places as needed.

Assume that population mean is to be estimated from the sample
size n =100, Sample mean x = 76.0cm, standard deviation s = 4.0cm.
Use the results to approximate the margin of error and 95%
confidence interval.

Use the formula to find the standard error of the distribution
of differences in sample means, .
Samples of size 120 from Population 1 with
mean 87 and standard deviation 14 and samples
of size 85 from Population 2 with mean 71 and
standard deviation 17
Round your answer for the standard error to two decimal
places.
standard error
=

consider the following results frmo two independent random
samples taken from two populations. assume that the variances are
NOT equal.
Population 1
population 2
sample size
50
50
sample mean
35
30
sample variance
784
100
a) what is the "degrees of freedom" for these data?
b) what is the 95% confidence interval difference of the
population means?

Use the formula to find the standard error of the distribution
of differences in sample means, x¯1-x¯2 . Samples of size 50 from
Population 1 with mean 4.0 and standard deviation 1.6 and samples
of size 50 from Population 2 with mean 1.5 and standard deviation
1.2 Round your answer for the standard error to two decimal places.
standard error = Enter your answer in accordance to the question
statement

The following results are for independent random samples taken
from two populations.
Sample 1
Sample 2
n1 = 40
n2 = 50
x1 = 32.2
x2 = 30.1
s1 = 2.6
s2 = 4.3
(a) What is the point estimate of the difference between the two
population means?
(b) What is the degrees of freedom for the t
distribution?
(c) At 95% confidence, what is the margin of error?
(d) What is the 95% confidence interval for the difference
between...

Given two dependent random samples with the following
results:
Population 1
41
33
18
34
42
39
50
Population 2
50
29
29
28
47
24
44
Use this data to find the 95% confidence interval for the true
difference between the population means. Assume that both
populations are normally distributed.
Step 1 of 4:
Find the point estimate for the population mean of the paired
differences. Let x1 be the value from Population 1 and x2 be the
value...

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