Question

Find the​ z-score corresponding to the given value and use the​ z-score to determine whether the value is unusual. Consider a score to be unusual if its​ z-score is less than minus2 or greater than 2. Round to the nearest hundredth if necessary. A weight of 103.2 pounds among a population having a mean weight of 162.0 pounds and a standard deviation of 22.6 pounds.

Answer 1

GIVEN THAT :-

According to the question we have that ,

the given mean =162.0

standared deviation =22.6

now

TO FIND :- the Z score for 103.2

so for finding the Z score  we have a formula :

Zscore = (x-mean)/standarddeviation

=(103.2-162.0)/22.6

Zscore= -2.60

Round Z score value up to Round to the nearest hundredth i.e round to 2 decimal place

there fore Zscore = -2.60

a score to be unusual if its​ z-score < -2 or Z score > 2

there fore Zscore = -2.60 : unusual

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