Question

Find the​ z-score corresponding to the given value and use the​ z-score to determine whether the value is unusual. Consider a score to be unusual if its​ z-score is less than minus2 or greater than 2. Round to the nearest hundredth if necessary. A body temperature of 96.59degrees F given that human body temperatures have a mean of 98.20degrees F and a standard deviation of 0.62 degrees.

Answer 1

Mean = 98.20 degree

Standard deviation = 0.62 degree

We find Z score for 96.59 degree

i.e x = 96.59

Formula for Z score

Round Z score value up to Round to the nearest hundredth i.e round to 2 decimal place

Z score = - 2.60

a score to be unusual if its​ z-score < -2 or Z score > 2

Here our calculated Z score is -2.60 < - 2   So It unusual

Final answer :-

Z score = - 2.60 ;and unusual