The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual. For a sample of n equals 60, find the probability of a sample mean being less than 24.2 if mue quals24 and sigma equals 1.2.
Would the given sample mean be considered unusual?
Solution :
_{} = / n = 1.2 / 60
P( < 24.2)
= P(( - _{} ) / _{} < (24.2 - 24) / 1.2 / 60 )
= P(z < 1.29)
= 0.9015
Given sample mean is not unusual because probability > 0.05
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