The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual.
For a sample of n=62, find the probability of a sample mean being less than 22.6 if μ=23 and sigmaσ=1.18 is?
mean = = 23
standard deviation = = 1.18
n = 62
= / n = 1.18/ 62 = 0.15
P( < 22.6) = P[( - ) / < (22.6-23) /0.15 ]
= P(z <-2.67 )
Using z table
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