Question

The population mean and standard deviation are given below. Find the required probability and determine whether the given sample mean would be considered unusual.

For a sample of n=62, find the probability of a sample mean being less than 22.6 if μ=23 and sigmaσ=1.18 is?

Answer #1

solution

mean = = 23

standard deviation = = 1.18

n = 62

= 23

= / n = 1.18/ 62 = 0.15

P( < 22.6) = P[( - ) / < (22.6-23) /0.15 ]

= P(z <-2.67 )

Using z table

= 0.0038

probability= 0.0038

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LOADING...
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LOADING...
Click the icon to view page 2 of the standard normal table.
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