A sample of 31 IQ scores are selected from 100 IQ scores. Those scores produce a mean and population standard deviation of 132 and 10, respectively. Find the 95% confidence interval for the annual average of IQ scores.
Solution :
Given that,
Sample size = n = 31
Z/2 = 1.96
Margin of error = E = Z/2* ( /n)
= 1.96 * ( 10/ 31)
Margin of error = E = 3.52
At 95% confidence interval estimate of the population mean is,
- E < < + E
132 - 3.52 < < 132 + 3.52
128.48 < < 135.52
(128.48 , 135.52)
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