Scores on an IQ test are normally distributed. A sample of 12 IQ scores had standard deviation s=6 (a) Construct a 95% confidence interval for the population standard deviation σ. Round the answers to at least two decimal places. (b) The developer of the test claims that the population standard deviation is σ=7 Does this confidence interval contradict this claim? Explain.
Answer:
a)
Given,
degree of freedom = n - 1
= 12 - 1
= 11
alpha = 0.05
alpha/2 = 0.025
(0.025,11) = 21.92004926 [since from critical chi square table]
(0.975,11) = 3.81574825
To construct 95% CI
Interval = (sqrt((n-1)s^2/(alpha/2) , sqrt((n-1)s^2/(1-alpha/2))
= sqrt(11*6^2/21.92) , sqrt(11*6^2/3.82)
= (18.07 , 10.18)
b)
Ho : σ = 7
Ha : σ != 7
Here we can say yes, due to that the CI doesn't contain 7
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