An automobile manufacturer who wishes to advertise that one of its models achieves 30 mpg (miles per gallon) decides to carry out a fuel efficiency test. Six nonprofessional drivers were selected, and each one drove a car from Phoenix to Los Angeles. The resulting fuel efficiencies (in miles per gallon) are given below.
27.1 | 29.2 | 31.3 | 28.4 | 30.2 | 29.6 |
Assuming that fuel efficiency is normally distributed under these circumstances, do the data contradict the claim that true average fuel efficiency is (at least) 30 mpg? Test the appropriate hypotheses at significance level 0.05. (Use a statistical computer package to calculate the P-value. Round your test statistic to two decimal places and your P-value to three decimal places.)
t=
P-value=
For the given data sample mean is
Create the following table.
data | data-mean | (data - mean)2 |
27.1 | -2.2 | 4.84 |
29.2 | -0.1 | 0.01 |
31.3 | 2 | 4 |
28.4 | -0.9 | 0.81 |
30.2 | 0.9 | 0.81 |
29.6 | 0.3 | 0.09 |
Find the sum of numbers in the last column to get.
So standard deviation is
Here hypothesis is
vs
Hence test statistics is
As it is left tailed test P value is TDIST(1.18,5,1)=0.146
Get Answers For Free
Most questions answered within 1 hours.