The space shuttle’s external tank holds cryogenic propellants. If the number of liters per tank lies along a normal curve with a mean of 2 million and a standard deviation of four hundred thousand (0.4 million), find the percentage of tanks which hold exactly 1.8 million liters.
Solution:
We are given
Variable follows normal distribution with
µ = 2 million
σ = 0.4 million
We have to find P(X=1.8)
So, by using approximation, we have
P(X=1.8) = P(1.8 - 0.5 < X < 1.8 + 0.5) = P(1.3 < X < 2.3)
P(1.3 < X < 2.3) = P(X < 2.3) - P(X < 1.3)
Find P(X < 2.3)
Z = (X - µ)/σ
Z = (2.3 - 2)/0.4
Z = 0.75
P(Z < 0.75) = P(X < 2.3) = 0.773373
(by using z-table)
Now, find P(X < 1.3)
Z = (X - µ)/σ
Z = (1.3 - 2)/0.4
Z = -1.75
P(Z < -1.75) = P(X < 1.3) = 0.040059
(by using z-table)
P(1.3 < X < 2.3) = P(X < 2.3) - P(X < 1.3)
P(1.3 < X < 2.3) = 0.773373 - 0.040059
P(1.3 < X < 2.3) = 0.733314
P(X=1.8) = 0.733314
Required probability = 0.733314
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