The number of flaws per square yard in a type of carpet material varies with mean 1.8 flaws per square yard and standard deviation 0.9 flaws per square yard. This population distribution cannot be normal, because a count takes only whole-number values. An inspector studies 178 square yards of the material, records the number of flaws found in each square yard, and calculates x, the mean number of flaws per square yard inspected. Use the central limit theorem to find the approximate probability that the mean number of flaws exceeds 1.9 per square yard. (Round your answer to four decimal places.)
By Central Limit Theorem, the sampling distribution of sampling mean is normal distribution irrespective of population shape.
= 1.8
= 0.9
n = 178
SE = /
= 0.9/
= 0.0675
To find P(>1.9)
Z = (1.9 - 1.8)/0.0675
= 1.4824
Table gives area = 0.4306
So,
P(>1.9) = 0.5 - 0.4306 =0.0694
So,
Answer is:
0.0694
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