A researcher asks a large population of people (several thousand) how many times per year they attend religious services. The mean number is 17 and the standard deviation is 7. You recruit a random sample of 144 people and ask them the same question. The mean for the sample is 17.75. First, compute the standard error of the mean. Next, conduct a z test and use Table Z to find the area of the normal curve that falls beyond the z score you obtained.
Here, we have to use one sample z test for the population mean.
The null and alternative hypotheses are given as below:
H0: µ = 17 versus Ha: µ ≠ 17
This is a two tailed test.
The test statistic formula is given as below:
Z = (Xbar - µ)/[σ/sqrt(n)]
From given data, we have
µ = 17
Xbar = 17.75
σ = 7
n = 144
α = 0.05
Critical value = -1.96 and 1.96
(by using z-table or excel)
Z = (17.75 - 17)/[7/sqrt(144)]
Z = 1.2857
P-value = 0.1985
(by using Z-table)
P-value > α = 0.05
So, we do not reject the null hypothesis
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