Often, frequency distributions are reported using unequal class widths because the frequencies of some groups would otherwise be small or very large. Consider the following data, which represent the daytime household temperature the thermostat is set to when someone is home for a random sample of 746 households. Determine the class midpoint, if necessary, for each class and approximate the mean and standard deviation temperature.
Temperature (deg F) |
Lower Limit |
Upper Limit |
Frequency |
61-64 |
61 |
64.99 |
32 |
65-67 |
65 |
67.99 |
66 |
68-69 |
68 |
69.99 |
195 |
70 |
70 |
70.99 |
190 |
71-72 |
71 |
72.99 |
118 |
73-76 |
73 |
76.99 |
90 |
77-80 |
77 |
80.99 |
48 |
1a.
Class |
Class Midpoint |
|
61- |
64 |
|
65– |
67 |
|
68 |
69 |
|
70 |
||
71– |
72 |
|
73– |
76 |
|
77– |
80 |
(Round to one decimal place as needed.)
1b.
The sample mean is degrees°F. (Round to one decimal place as needed.)
2c. The sample standard deviation is degrees°F. (Round to one decimal place as needed.)
Sample mean = 70.8 0F
Sample standard deviation = 3.4 0F
Complete solution is given in attached image:
Thank You...!
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