Question

According to LIMRA, 75% of husband-wife families with kids under 18 years old have life insurance....

According to LIMRA, 75% of husband-wife families with kids under 18 years old have life insurance. A random sample of seven husband-wife families was selected. What is the standard deviation of this distribution?

Homework Answers

Answer #1

p = Probability of success = 0.75 ( We converted 75 % in to decimal )

n = random sample size =   7   ( A random sample of seven husband-wife families was selected)

Here we use formula of standard deviation from binomial distribution beause we have given the

Final answer :-

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
The plaintiffs were a husband and wife who tested positive for HIV in a life insurance...
The plaintiffs were a husband and wife who tested positive for HIV in a life insurance application physical. The independent laboratory reported the HIV status to the insurance company, which sent a notice of rejection to the couple. The insurance company also advised that it would disclose the reason for their rejection to their physician if they so wished. The plaintiffs took no action. Two years later, the wife was diagnosed with AIDS, and on inquiry, she and her husband...
The life expectancy in the United States is 75 years with a population standard deviation of...
The life expectancy in the United States is 75 years with a population standard deviation of 7 years. A random sample of 49 individuals is selected. What is the probability that the sample mean will be less than 72.5 years
According to an​ almanac, 60% of adult smokers started smoking before turning 18 years old. ​(a)...
According to an​ almanac, 60% of adult smokers started smoking before turning 18 years old. ​(a) If 400 adult smokers are randomly​ selected, how many would we expect to have started smoking before turning 18 years​ old? We would expect about _______ adult smokers to have started smoking before turning 18 years old.​(Type a whole​ number.) ​(b) Would it be unusual to observe 340 smokers who started smoking before turning 18 years old in a random sample of 400 adult​...
According to an​ almanac, 70​% of adult smokers started smoking before turning 18 years old. ​...
According to an​ almanac, 70​% of adult smokers started smoking before turning 18 years old. ​ (a) Compute the mean and standard deviation of the random variable​ X, the number of smokers who started before 18 in 300 trials of the probability experiment. ​(b) Interpret the mean. ​(c) Would it be unusual to observe 240 smokers who started smoking before turning 18 years old in a random sample of 300 adult​ smokers? Why?
According to an​ almanac, 60​% of adult smokers started smoking before turning 18 years old. ​(a)...
According to an​ almanac, 60​% of adult smokers started smoking before turning 18 years old. ​(a) Compute the mean and standard deviation of the random variable​ X, the number of smokers who started before 18 in 400 trials of the probability experiment. ​(b) Interpret the mean. ​(c) Would it be unusual to observe 360 smokers who started smoking before turning 18 years old in a random sample of 400 adult​ smokers? Why?
According to an​ almanac, 60​% of adult smokers started smoking before turning 18 years old. ​(a)...
According to an​ almanac, 60​% of adult smokers started smoking before turning 18 years old. ​(a) If 100 adult smokers are randomly​ selected, how many would we expect to have started smoking before turning 18 years​ old? ​(b) Would it be unusual to observe 80 smokers who started smoking before turning 18 years old in a random sample of 100 adult​ smokers? Why? A- We would expect about ____adult smokers to have started smoking before turning 18 years old. B-Would...
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 69 inches and standard...
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 69 inches and standard deviation 6 inches. (b) If a random sample of twenty-seven 18-year-old men is selected, what is the probability that the mean height x is between 68 and 70 inches? (Round your answer to four decimal places.)
A medical researcher claims that 5% of children under 18 years of age have asthma. In...
A medical researcher claims that 5% of children under 18 years of age have asthma. In a random sample of 300 children under 18 years of age, 24 children had asthma. Is this evidence that more than 5% of children under 18 years of age have asthma? The null and alternative Hypotheses for the Test are: HO : p = 0.05 HA : p > 0.05 The P-value for this test is 0.0086. What does the P-value mean in the...
1, According to an​ airline, flights on a certain route are on time 75​% of the...
1, According to an​ airline, flights on a certain route are on time 75​% of the time. Suppose 10 flights are randomly selected and the number of​ on-time flights is recorded. ​(a) Explain why this is a binomial experiment. ​(b) Find and interpret the probability that exactly 6 flights are on time. ​(c) Find and interpret the probability that fewer than 6 flights are on time. ​(d) Find and interpret the probability that at least 6 flights are on time....
According to a recent poll, 80% of the respondents who were 18 years or older stated...
According to a recent poll, 80% of the respondents who were 18 years or older stated that the minimum voting age should be 18. A random sample of 8 respondents was taken a) Is this a binomial experiment? If so identify p and q . b) Find the mean and standard deviation. c) find the probability that i) exactly 5 believe that the minimum voting age should be 18. ii) more than 5 believe the minimum voting age should be...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT