The life expectancy in the United States is 75 years with a population standard deviation of 7 years. A random sample of 49 individuals is selected. What is the probability that the sample mean will be less than 72.5 years
Solution :
Given that ,
mean = = 75
standard deviation = = 7
n = 49
= 75
= / n =7 / 49=1
P( < 72.5) = P[( - ) / < (72.5 -75) /1 ]
= P(z < -2.5)
Using z table
= 0.0062
probability=0.0062
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