Question

Hi, Please disregard the first question I asked the same like this. This is the updated one.

Please answer the problem below.

Thank you,

The number of hits to a website follows a Poisson process. Hits occur at the rate of 0.9 per minute between​ 7:00 P.M. and 11​:00 P.M. Given below are three scenarios for the number of hits to the website. Compute the probability of each scenario between 10 : 33 P.M. and 10​:43 P.M. Interpret each result.

​(a) exactly six ​

(b) fewer than six

​(c) at least six ​

(a)​ P(6​) = _________ ​(Round to four decimal places as​ needed.)

(b) fewer than six = _________ ​(Round to four decimal places as​ needed.)

​(c) at least six= _________ ​(Round to four decimal places as​ needed.)

Answer 1

Since the hits occur at the rate of 0.9 per minute and there are 10 minutes in between 10:33 P. M to 10:43 PM

So average number of hits in this period of time is ​​​​​​

Now using Poisson distribution we have probability of r number of hits in the given period equal to

a)

b) Required probability is

c) This event is the complement of the event given in b) So the required probability is