Hello please Use the following discrete probability distribution below to answer the following questions:
X p(x)
1 0.16
2 0.17
3 0.33
4 0.16
5 0.10
6 UNKNOWN
1. a What is the probability that x = 6?
P(6) = 0.08 P(6) = 0.18 P(6) = 0.24 P(6) = 0.35
1.b) What is the mean of the probability distribution?
µ = 2.92 µ = 3.11 µ = 3.51 µ = 4.00
1.c) What is the standard deviation?
σ = 0.98 σ = 1.22 σ = 1.44 σ = 1.96
Now what if Bob invests in three stocks. His return in dollars and the probability for each return is listed below.
Stock A $300 p= 0.50
Stock B $600 p= 0.30
Stock C $800 p= 0.20
What is Bob’s expected return for the stocks in his portfolio?
1a) P(X = 6) is computed by using the property that the sum of
all probabilities across the X range should be 1. Therefore we get
here:
P(X = 6) = 1 - 0.16 - 0.17 - 0.33 - 0.16 - 0.1 = 0.08
Therefore P(6) = 0.08 is the required probability
here.
1b) The mean of the probability distribution here is computed
as:
Mean = 1*0.16 + 2*0.17 + 3*0.33 + 4*0.16 + 5*0.1 + 6*0.08 =
3.11
Therefore b) 3.11 is the required mean here.
1c) The second moment of X is first computed here as:
E(X2) = 12*0.16 + 22*0.17 +
32*0.33 + 42*0.16 + 52*0.1 +
62*0.08 = 11.75
Therefore the standard deviation is computed here as:
Therefore 1.44 is the required standard deviation
here.
The expected return is computed as the sum product of returns with the probability:
= 300*0.5 + 600*0.3 + 800*0.2
= 490
Therefore d) 490 is the expected return here.
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