Consider the following discrete probability distribution. |
x | −15 | −5 | 15 | 20 |
P(X = x) | 0.52 | 0.13 | 0.16 | |
. |
Complete the probability distribution. (Round your answer to 2 decimal places.) |
P(X = 15) |
c. |
What is the probability that the random variable X is positive? (Round your answer to 2 decimal places.) |
Probability |
d. |
What is the probability that the random variable X is greater than −10? (Round your answer to 2 decimal places.) |
Probability |
e. |
What is the probability that the random variable X is less than 20? (Round your answer to 2 decimal places.) |
Probability |
Part B)
P(X = 15) = ?
x | −15 | −5 | 15 | 20 |
P(X = x) | 0.52 | 0.13 | 0.19 | 0.16 |
We know that sum of probability = 1
P(X=-15) +P(X=-5) +P(X=15) +P(X=20) = 1
P(X=15) = 1-0.52-0.13-0.16 = 0.19 Ans
Part C
Probability that the random variable X is positive?
P(X=15) +P(X=20) = 0.19 + 0.16 = 0.35
Part D
Probability that the random variable X is greater than −10?
P(X=-5) +P(X=15) +P(X=20) = 0.13+0.19 + 0.16 = 0.48
Part E)
probability that the random variable X is less than 20
P(X=-15) +P(X=-5) +P(X=15) = 0.52+0.13+0.19 =0.84
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