Question

The following table contains the probability distribution for the number of traffic accidents daily in a small town. Complete parts (a) and (b) to the right. Number of Accidents Daily (X) P(X) 0 0.30 0.30 1 0.34 0.34 2 0.17 0.17 3 0.08 0.08 4 0.06 0.06 5 0.04 0.04 6 0.01 0.01 b. Compute the standard deviation. sigma σ equals = nothing (Type an integer or decimal rounded to three decimal places as needed.)

Answer #1

Solution :

solution

Mean = = X * P(X)

= 0 * 0.30+ 1 * 0.34+ 2 * 0.17+ 3 * 0.08 + 4 * 0.06+5 * 0.04+ 6* 0.01

= ( 0+0.34 +0.34 +0.24+0.24+0.2+0.06 )

= 1.42

Standard deviation =

=X 2 * P(X) - 2

= [ 02 * 0.30+ 12 * 0.34+ 22 * 0.17+ 32 * 0.08 + 4 2* 0.06+5 2* 0.04+ 6*2 0.01] -1.422

= [(0 +0.34+0.68 +0.72+0.96+1 + 0.36) )]-2.0164

= 4.06-2.0164

=2.0436

Standard deviation = =1.430

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