Computers are shut down for certain periods of time for routine maintenance, installation of new hardware, and so on. The downtimes for a particular computer are normally distributed with a mean, , of 1.5 hours and a standard deviation, , of 0.4 hours.
Find the probability a downtime will exceed 0.5 hours.
4 points
QUESTION 16
Find the probability a downtime will be between 2 and 2.5 hours.
Solution :
P(x > 0.5) = 1 - P(x < 0.5)
= 1 - P[(x - ) / < (0.5 - 1.5) / 0.4)
= 1 - P(z < -2.5)
= 1 - 0.0062
= 0.9938
Probability = 0.9938
16.
P(2 < x < 2.5) = P[(2 - 1.5)/ 0.4) < (x - ) / < (2.5 - 1.5) / 0.4) ]
= P(1.25 < z < 2.5)
= P(z < 2.5) - P(z < 1.25)
= 0.9938 - 0.8944
= 0.0994
Probability = 0.0994
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