Rock-Paper-Scissors
The table below shows the choices made by 122 players on the first
turn of a Rock-Paper-Scissors game. Recall that rock beats scissors
which beats paper which beats rock. A player gains an advantage in
playing this game if there is evidence that the choices made on the
first turn are not equally distributed among the three options. Use
a goodness-of-fit test to see it there is evidence that any of the
proportions are different from 1 3 .
Option Selected | Frequency |
---|---|
Rock | 65 |
Paper | 43 |
Scissors | 14 |
Total | 122 |
Table 1 Frequencies for first turn in
Rock-Paper-Scissors
Calculate the chi-square test statistic and the
p-value.
Round your answer for the chi-square statistic to two decimal
places, and your answer for the p-value to three decimal
places.
χ 2 =
p-value =
hypothesis:-
all the proportions are equal to 1/3
at least one of the proportions are different from 1/3
the necessary calculation table:-
category | observed | expected | |
rock | 65 | 122*1/3 = 40.6667 | (65-40.6667)2/40.6667= 14.5601 |
paper | 43 | 40.6667 | 0.1339 |
scissor | 14 | 40.6667 | 17.4863 |
sum=122 | sum = 32.1803 |
the test statistic be:-
df = (3-1) = 2
the p value is :-
[ in any blank cell of excel type =CHISQ.DIST.RT(32.18,2) ]
decision:-
p value = 0.000 < 0.05 (Alpha)
we reject the null hypothesis. There is sufficient evidence that any of the proportions are different from 1/3.
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