Consider the following competing hypotheses and accompanying
sample data. (You may find it useful to reference the
appropriate table: z table or t
table)
H_{0}: p_{1} −
p_{2} ≥ 0
H_{A}: p_{1} −
p_{2} < 0
x_{1} = 250 | x_{2} = 275 |
n_{1} = 400 | n_{2} = 400 |
a. Calculate the value of the test statistic.
(Negative value should be indicated by a minus sign. Round
intermediate calculations to at least 4 decimal places and final
answer to 2 decimal places.)
b. Find the p-value.
p-value < 0.01
0.01 ≤ p-value < 0.025
0.025 ≤ p-value < 0.05
0.05 ≤ p-value < 0.10
p-value ≥ 0.10
c. At the 5% significance level, what is the
conclusion to the test?
Reject H_{0} since the p-value is less than significance level.
Reject H_{0} since the p-value is greater than significance level.
Do not reject H_{0} since the p-value is less than significance level.
Do not reject H_{0} since the p-value is greater than significance level.
d. Interpret the results at αα = 0.05.
We conclude that the population proportions differ.
We cannot conclude that the population proportions differ.
We conclude that population proportion 2 is greater than population proportion 1.
We cannot conclude that population proportion 2 is greater than population proportion 1.
rev: 01_22_2019_QC_CS-154677
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Question8of8Total8 of
The estimate of the sample proportion is ,
The pooled estimate is ,
The null and alternative hypothesis is ,
a.The test statistic is ,
b. The p-value is ,
p-value= ; From standard normal distribution table
0.025 < p-value < 0.05
c.
Reject Ho , since the p-value is less than significance level 0.05
d. Conclusion : We conclude that population proportion 2 is greater than population proportion 1.
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