The oil production at a refinery is normally distributed with a mean of 230,000 barrels per day with a standard deviation of 7,500 barrels.
1. As the normal distribution is symmetrical about its mean, the P(X>Mean+a) = P(X<mean-a). So here the probability of producing more than 240,000 is same as probability of production less than 230,000.
2. P(X>245,000) = P((X-230,000)/7500> 2) = 1- 0.9772499 = 0.022750
3. P(X<220,000) = P((X-230,000)/7500 < -1.333) = 0.09121127 = 0.091211
4. There is 25% chance of producing more than 235,058.7 (235,059) barrels per day.
Which is basically 0.6744898*7500 + 230,000
Thanks
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