Question

The mean daily production of a herd of cows is assumed to be normally distributed with a mean of 36 liters, and standard deviation of 4.8 liters. A) What is the probability that daily production is less than 45.7 liters? Answer= (Round your answer to 4 decimal places.) B) What is the probability that daily production is more than 22.8 liters? Answer= (Round your answer to 4 decimal places.) Warning: Do not use the Z Normal Tables...they may not be accurate enough since WAMAP may look for more accuracy than comes from the table.

Answer 1

This is a normal distribution question with

a) P(x < 45.7)=?
The z-score at x = 45.7 is,

z = 2.0208
This implies that
P(x < 45.7) = P(z < 2.0208) = 0.9784
b) P(x > 22.8)=?
The z-score at x = 22.8 is,

z = -2.75
This implies that
P(x > 22.8) = P(z > -2.75) = 1 - 0.003
P(x > 22.8) = 0.997
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