H0:μ=11.8H0:μ=11.8
H1:μ<11.8H1:μ<11.8
Your sample consists of 306 subjects, with a mean of 11.5 and
standard deviation of 4.72.
Calculate the test statistic, rounded to 2 decimal places.
this is the left tailed test .
The null and alternative hypothesis is ,
H0 : = 11.8
Ha : < 11.8
Test statistic = z
= ( - ) / / n
= (11.5-11.8) / 4.72/ 306
= -1.11
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