Question

# A new kind of typhoid shot is being developed by a medical research team. The old...

A new kind of typhoid shot is being developed by a medical research team. The old typhoid shot was known to protect the population for a mean time of 36 months, with a standard deviation of 3 months. To test the time variability of the new shot, a random sample of 23 people were given the new shot. Regular blood tests showed that the sample standard deviation of protection times was 2.1 months. Using a 0.05 level of significance, test the claim that the new typhoid shot has a smaller variance of protection times.

(a) What is the level of significance?

State the null and alternate hypotheses.

Ho: σ2 = 9; H1: σ2 < 9Ho: σ2 < 9; H1: σ2 = 9    Ho: σ2 = 9; H1: σ2 ≠ 9Ho: σ2 = 9; H1: σ2 > 9

(b) Find the value of the chi-square statistic for the sample. (Round your answer to two decimal places.)

What are the degrees of freedom?

What assumptions are you making about the original distribution?

We assume a normal population distribution.We assume a uniform population distribution.    We assume a exponential population distribution.We assume a binomial population distribution.

(c) Find or estimate the P-value of the sample test statistic.

P-value > 0.1000.050 < P-value < 0.100    0.025 < P-value < 0.0500.010 < P-value < 0.0250.005 < P-value < 0.010P-value < 0.005

(d) Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis?

Since the P-value > α, we fail to reject the null hypothesis.Since the P-value > α, we reject the null hypothesis.    Since the P-value ≤ α, we reject the null hypothesis.Since the P-value ≤ α, we fail to reject the null hypothesis.

(e) Interpret your conclusion in the context of the application.

At the 5% level of significance, there is insufficient evidence to conclude that the new typhoid shot has a smaller variance of protection times.At the 5% level of significance, there is sufficient evidence to conclude that the new typhoid shot has a smaller variance of protection times.

(f) Find a 90% confidence interval for the population standard deviation. (Round your answers to two decimal places.)

 lower limit upper limit

Interpret the results in the context of the application.

We are 90% confident that σ lies above this interval.We are 90% confident that σ lies outside this interval.    We are 90% confident that σ lies within this interval.We are 90% confident that σ lies below this interval.

a) level of significance =0.05

Ho: σ2 = 9; H1: σ2 < 9

b)

value of the chi-square statistic =(23-1)*(2.1/3)2 =10.78

degrees of freedom =23-1=22

We assume a normal population distribution.

c) 0.010 < P-value < 0.025

d)

Since the P-value ≤ α, we reject the null hypothesis

e)

At the 5% level of significance, there is sufficient evidence to conclude that the new typhoid shot has a smaller variance of protection times.

f)

lower limit =1.69

upper limit =2.80

We are 90% confident that σ lies within this interval.

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