A population has a standard deviation of 24. If a sample of size 64 is selected from this population, what is the probability that the sample mean will be within ±3 of the population mean?
Question 3 options:
-1.96 |
|
-0.4619 |
|
0.95 |
|
0.3413 |
|
0.645 |
|
0.6826 |
|
0.4875 |
|
Since the mean is not given, there is no answer to this question. |
Solution:
0.6826
Explanation:-
First, we compute the standard error,
= 3
Now, we compute the z-scores
Z = -3/3
Z = -1
Z = 3/3
Z = 1
Using Z-tables, the probability between -1 and 1 is
P (-1 < Z < 1) = P (Z 1) - P (Z - 1)
= 0.8413 - 0.1587
= 0.6826
Hence, the probability that the sample mean will be within ±3 of the population mean is 0.6826.
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