Question

Given μ1=0, μ3=1, and 0≤ μ2≤1, show that SUM(μ1- μ.)2 is minimized when μ2=0.5 where μ....

Given μ1=0, μ3=1, and 0≤ μ2≤1, show that SUM(μ1- μ.)2 is minimized when μ2=0.5 where μ. = (μ1+ μ2+ μ3)/3

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Answer #1

Another method can be that we have to minimize the variance*3 and variance is minimum for the symmetric data so variance will be minimum when 1 and  2have the same difference as  2and  3

So by equating them, we can find  2 = 0.5

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