A sample of 19 paired observations generates the following data: d = 1.2 and s2DsD2 = 2.4. Assume a normal distribution.
a. Construct the 95% confidence interval for the mean difference μD. (Round intermediate calculations to at least 4 decimal places and final answers to 2 decimal places.)
Confidence interval is_________to__________.
b. Using the confidence interval, test whether the mean difference differs from zero.
There is evidence that the mean difference differs from zero.
There is no evidence that the mean difference differs from zero.
solution:-
a. given that d = 1.2 , n = 19
and sd^2 = 2.4 then sd = 1.5492
degree of freedom df = n - 1 = 19 - 1 = 18
we look into t table with df = 18 and with 95% two tailed probability
critical value t = 2.101
confidence interval formula
=> d +/- t * sd/sqrt(n)
=> 1.2 +/- 2.101 * 1.5492/sqrt(19)
=> 0.45 to 1.95
b. Using the confidence interval, test whether the mean difference
differs from zero.
=> There is no evidence that the mean difference differs from zero.
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