Question

In a survey of 2808 adults, 1413 say they have started paying bills online in the last year. Construct a 99% confidence interval for the population proportion. Interpret the results. A 99% confidence interval for the population proportion is left parenthesis nothing comma nothing right parenthesis . (Round to three decimal places as needed.) Interpret your results. Choose the correct answer below. A. With 99% confidence, it can be said that the sample proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval. B. With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval. C. The endpoints of the given confidence interval show that adults pay bills online 99% of the time

Answer #1

sample proportion, pcap = 1413/ 2808 = 0.5032

sample size, n = 2808

Standard error, SE = sqrt(pcap * (1 - pcap)/n)

SE = sqrt(0.5032 * (1 - 0.5032)/2808) = 0.0094

For 99% Confidence level, the z-value = 2.58

CI = (pcap - z*SE, pcap + z*SE)

CI = (0.5032 - 2.58 * 0.0094 , 0.5032 + 2.58 * 0.0094)

CI = (0.479 , 0.527)

With 99% confidence, it can be said that the population proportion of adults who say they have started paying bills online in the last year is between the endpoints of the given confidence interval.

In a survey of 2667 ?adults, 1422 say they have started paying
bills online in the last year. Construct a? 99% confidence interval
for the population proportion. Interpret the results. A? 99%
confidence interval for the population proportion is left
parenthesis nothing comma nothing right parenthesis . ?(Round to
three decimal places as? needed.) Interpret your results. Choose
the correct answer below. A. The endpoints of the given confidence
interval show that adults pay bills online? 99% of the time....

In a survey of 3287 adults, 1459 say they have started paying
bills online in the last year. Construct a 99% confidence interval
for the population proportion. Interpret the results.
A 99% confidence interval for the population proportion is left
parenthesis nothing comma nothing right parenthesis . (Round to
three decimal places as needed.)
Interpret your results. Choose the correct answer below.
A. The endpoints of the given confidence interval show that
adults pay bills online 99% of the time....

In a survey of 3447 adults, 1453 say they have started paying
bills online in the last year. Construct a 99% confidence interval
for the population proportion. Interpret the results. A 99%
confidence interval for the population proportion is left
parenthesis nothing comma nothing right parenthesis . (Round to
three decimal places as needed.) Interpret your results. Choose
the correct answer below. A. The endpoints of the given confidence
interval show that adults pay bills online 99% of the time....

In a survey of 3398 adults, 1487 say they have started paying
bills online in the last year. Construct a 99% confidence interval
for the population proportion. Interpret the results. A 99%
confidence interval for the population proportion is (___,___).
(Round to three decimal places as needed.) Interpret your results.
Choose the correct answer below.
A. With 99% confidence, it can be said that the population
proportion of adults who say they have started paying bills online
in the last...

In a survey of 2674 adults, 1470 say they have started paying
bills online in the last year. Construct a 99% confidence interval
for the population proportion. Interpret the results.
1) The 90% confidence interval for the population proportion p
is (_,_) (Round to three decimal places as needed.)
Interpret your results. Choose the correct answer below.
A. With 99% confidence, it can be said that the population
proportion of adults who say they have started paying bills online
in...

In a survey of 3123 adults, 1492 say they have started paying
bills online in the last year.
1. Construct a 99% confidence interval for the population
proportion. ______-
2. Interpret the results. (multiple choice)
A. The endpoints of the given confidence interval show that
adults pay bills online 99% of the time.
B.With 99% confidence, it can be said that the population
proportion of adults who say they have started paying bills online
in the last year is between...

In a survey of 3125 adults,1415 say they have started paying
bills online in the last year. Construct a 99% confidence interval
for the population proportion. Interpret the results.
A. 99% confidence interval for the population proportion
is______ (Round to three decimal places as needed.)
Interpret your results. Choose the correct answer below.
A. With 99% confidence, it can be said that the population
proportion of adults who say they have started paying bills online
in the last year is...

In a survey of
34783478
adults,
14341434
say they have started paying bills online in the last year.
Construct a 99% confidence interval for the population
proportion. Interpret the results.
A 99% confidence interval for the population proportion is
left parenthesis nothing comma nothing right parenthesis,.
(Round to three decimal places as needed.)

In a survey of 2548 adults, 1413 say they have started paying
bills online in the last year. Construct a 99% confidence interval
for the population proportion. Interpret the results.

In a survey of 3367 adults, 1492 say they have started paying
bills online in the last year. Construct a 99% confidence interval
for the population proportion. Interpret the results. A 99%
confidence interval for the population proportion is

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 24 minutes ago

asked 47 minutes ago

asked 49 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago