Suppose that it is known that the number of items produced in a factory during a week is a random variable with mean 50.
If the variance of a weekâs production is known to equal 26, then what can be said about the probability that this weekâs production will be between 40 and 60?
Solution :
Given that,
mean = = 50
variance = 2 = 26
standard deviation = = 5.0990
P (40 < x < 60 )
P ( 40 - 50 / 5.0990) < ( x - / ) < ( 60 - 50 / 5.0990)
P ( - 10 / 5.0990< z < 10 / 5.0990 )
P (-1.96 < z < 1.96 )
P ( z < 1.96 ) - P ( z < -1.96)
Using z table
= 0.9750 - 0.0250
= 0.9500
Probability = 0.9500
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