A nurse at a local hospital is interested in estimating the birth weight of infants. How large a sample must she select if she desires to be 99% confident that the true mean is within 2 ounces of the sample mean? The standard deviation of the birth weights is known to be 5 ounces.
Solution :
Given that,
standard deviation =s = =5
Margin of error = E = 2
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.58
sample size = n = [Z/2* / E] 2
n = ( 2.58*5 /2 )2
n =41.6
Sample size = n =42
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