For this problem, carry at least four digits after the decimal
in your calculations. Answers may vary slightly due to
rounding.
A random sample of 5020 permanent dwellings on an entire
reservation showed that 1676 were traditional hogans.
(a) Let p be the proportion of all permanent dwellings on the entire reservation that are traditional hogans. Find a point estimate for p. (Round your answer to four decimal places.)
(b) Find a 99% confidence interval for p. (Round your answer to three decimal places.)
lower limit | |
upper limit |
Give a brief interpretation of the confidence interval.
(c) Do you think that np > 5 and nq > 5 are satisfied for this problem? Explain why this would be an important consideration.
a)
Point estimate of p = = 1676 / 5020 = 0.334
b)
99% confidence interval for p is
- Z * sqrt ( ( 1 - ) / n) < p < + Z * sqrt ( ( 1 - ) / n)
0.334 - 2.576 * sqrt( 0.334 * 0.666 / 5020) < P < 0.334 + 2.576 * sqrt( 0.334 * 0.666 / 5020)
0.317 < p < 0.351
Lower limit = 0.317
Upper limit = 0.351
c)
Since np = 5020 * 0.334 = 1976 > 5 and n(1-p) = 5020 * 0.666 = 3044 > 5
The conditions are satisfied.
In order to carry out this proportion test, we need to assume normal distribution .
So these conditions are necessary to satisfy.
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