Question

20. Fill in the blank. Historically, the average score of PGA golfers is 72.13 with a standard deviation of 1.825. A random sample of 48 golfers is taken. There is an 86% chance that the average score is less than ________ strokes.

a. 74.1

b. 72.41

c. 73.16

d. 75.85

Answer #1

Solution :

Given that,

mean = = 72.13

standard deviation = = 1.825

n = 48

_{}
= 72.13

_{}
=
/
n = 1.825 /
48 = 0.2634

P(Z < z) = 86%

P(Z < 1.08) = 0.86

z = 1.08

= z *
_{}+
_{}
= 1.08 * 0.2634 + 72.13 = 72.41

There is an 86% chance that the average score is less than 72.41 strokes.

option b) is corect

It is known that the average score of PGA golfers is 72.13 with
a standard deviation of 8.825. A random sample of 48 golfers is
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chance that the average score of the random sample of 48 golfers is
more than

It is known that the average score of PGA golfers is 72.13 with
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