Fill in the blank. In a drive thru performance study, the average service time for McDonald's is 198.46 seconds with a standard deviation of 5.71 seconds. A random sample of 78 times is taken. There is a 63% chance that the average drive-thru service time is less than ________ seconds.
1) 198.25
2) 196.57
3) 200.35
4) There is not enough information to determine this.
5) 198.67
Given, = 198.46 , = 5.71
Using central limit theorem,
P( < x) = P(Z < x - / ( / sqrt(n) ))
So,
We have to calculate such that P( < x) = 0.63
P(Z < x - / ( / sqrt(n) )) = 0.63
From Z table, z-score for the probability of 0.63 is 0.3319
x - / ( / sqrt(n) ) = 0.3319
x - 198.46 / (5.71 / sqrt(78) ) = 0.3319
Solve for x
X = 198.67
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